How do you find the domain of #f(x) = sqrt (x^2 - 2x + 5)#?

1 Answer
May 21, 2015

The domain of this function is the #RR# set or, in interval notation, #(-oo, oo)#.

This is because the condition that applies here is #x^2-2x+5>=0#.

The graph of the function #x^2-2x+5# shows us that this expression takes positive values for all x. Therefore, we have no restriction for our choice of x values, which can be any real number.

graph{x^2-2x+5 [-10.67, 9.33, -0.68, 9.32]}