How do you find the domain of #f(x) = (x+3)/(2x-5)#?

1 Answer
EZ as pi
May 6, 2016

The domain is the set of all the #x-#values.
#x epsilon RR, x != -5/2#

Explanation:

We have to decide if there are any values of #x# which are invalid.

Looking at the numerator, #x + 3#, there is no problem or restriction for a value of #x#. The numerator can even be equal to 0

However, the denominator of a fraction may not be equal to 0.
If #2x+ 5 =0#, then the value of #x# is #-5/2#

So, for the domain, #x epsilon RR, x != -5/2#

This reads as "#x# may be any real number except #-5/2#.

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