How do you find the domain of #f(x) =(x+4)/(x+2)#?

1 Answer
May 28, 2017

Answer:

Domain: #{x|x!=2}#

Explanation:

There are two ways you can impact the domain of a real-valued function. The first is plugging in any #x# value that would cause you to divide by zero. The other is plugging in #x# values that would cause an even root to be negative.

There are no square roots in this problem, but there is a fraction with #x# in the denominator. So we need to find where the denominator is zero.

#x+2=0# whenever #x=-2#

So, the domain is all values of #x# except for #x=-2#. This sentences is often written in mathematical short hand as

#{x|x!=2}#