Question

How do you find the domain of `g(x) = ln(2 - x - x ^2)`?

Answer 1

`-2< x <1`

Explanation:

The domain of the function are the values of `x` that give 1 value for `y`.

For this function, `g(x)` is valid when `2-x-x^2>0`

`-(x+2)(x-1)>0`

`x+2>0 or -x+1>0`

`x> -2 or x<1`

`-2< x <1`