How do you find the domain of #h(x)= sqrt(x-1)#?

1 Answer
Jun 22, 2015

Answer:

The domain is #x in [1;+oo)#

Explanation:

The domain is maximum subset of #RR# for which expression is defined. In this case the limitation of a domain is, that the expression under square root sign must be greater than or equal to zero (the square root of a negative number is not a real number).

So in this case we get:

#x-1>=0#

#x>=1#