# How do you find the domain of #h(x) = (x-1) / ( [x^3] - 9x) #?

##### 2 Answers

#### Explanation:

For this function, we can plug in any value of

So, to determine the domain, solve the denominator for zero:

So, the domain does not include

See below

#### Explanation:

Well let's factor the function first:

No removable discontinuities, so x cannot equal

So Domain in interval notation can be said to be:

Or in Set builder:

Graph:

graph{(x-1)/(x^3-9x) [-8.54, 11.46, 11, 21]}