Question

How do you find the domain of `p(x) =-(x-1)^2-1`?

Answer 1

`p(x) = -(x - 1)^2 - 1`

`p(x) = -(x^2 - 2x + 1) - 1`

`p(x) = -x^2 + 2x - 1 - 1`

`p(x) = -x^2 + 2x - 2`

This is a quadratic equation, so the domain (x-value range) is all real numbers, or `-oo -> oo`.