# How do you find the domain of sqrt(x+3)/((x+8)(x-2))?

Feb 13, 2017

The domain is x in [-3,2[uu]2,+oo[

#### Explanation:

What's under the square root sign is $\ge 0$ and we cannot divide by $0$

Therefore,

$x + 3 \ge 0$, $\implies$, $x \ge - 3$

and $x \ne - 8$

and $x \ne 2$

Therefore,

the domain is x in [-3,2[uu]2,+oo[