How do you find the domain of the function #f(x)= x/(x^2+2x-3)#?

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Answer 1 · 2015-04-10T02:48:04

Don't take even roots of negative numbers. -- No probhem there are no roots at all.

Don't try9 to divide by #0#. There is a division, so we need to make sure that #x^2+2x-3# is not #0#.

OK, so when is it #0#?

Solve #x^2+2x-3 = 0#

#(x+3)(x-1)=0#

#x= -3, 1#

These are the numbers we need to throw out of the domain. So tlhe domain is all real numbers except #-3,1.#

(In interval notation: #(-oo, -3) uu (-3, 1) uu (1,oo)#)