Question

How do you find the dy/dx for `tan x + sec y - y = 0`?

Answer 1

`dy/dx= sec^2x/(1-secy tany)`

Explanation:

Differentiate w.r.t x the terms,

`sec^2x +secy tany dy/dx-dy/dx=0`

`(1-secy tany) dy/dx= sec^2x`

`dy/dx= sec^2x/(1-secy tany)`