# How do you find the end behavior of f(x) = - 6x^2 + 14x + 21?

End behaviour of a function is decided by the sign of its leading term. The leading term here is $- 6 {x}^{2}$. It would always be negative whether x is positive or negative. That means, as x approaches +$\infty$ or -$\infty$, f(x) would always be negative. So, f(x) would fall to the left and also fall to the right in the interval (-$\infty , + \infty$)