# How do you find the equation, in standard form, with all integer coefficients, of the line perpendicular to x + 3y = 6 and passing through (-3, 5)?

##### 1 Answer

Feb 1, 2017

Desired equation is

#### Explanation:

Equation of a line that is perpendicular to

is of the form

Hence, the line perpendicular to

we should have

and therefore

and desired equation is

graph{(3x-y+14)(x+3y-6)=0 [-11.38, 8.62, -3.12, 6.88]}