# How do you find the equation of the circle given Center (5,0), r=12?

Jun 25, 2016

${x}^{2} + {y}^{2} - 10 x - 119 = 0$

#### Explanation:

The equation of the circle, when you know center and radius, is

${\left(x - {x}_{0}\right)}^{2} + {\left(y - {y}_{0}\right)}^{2} = {r}^{2}$

So

${\left(x - 5\right)}^{2} + {y}^{2} = {12}^{2}$

${x}^{2} - 10 x + 25 + {y}^{2} - 144 = 0$

${x}^{2} + {y}^{2} - 10 x - 119 = 0$