# How do you find the equation of the circle which has it centre at point (2,3) and passes through the origin?

##### 1 Answer

Nov 13, 2015

#### Explanation:

If the center is at

then the radius is

The general equation of a circle is

where

graph{(x-2)^2+(y-3)^2=13 [-6.875, 13.125, -2.88, 7.12]}