How do you find the equation of the circle with center #(–7, –6)# and radius #2#?

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Answer 1 · 2016-01-22T16:08:53

#(x+7)^2+(y+6)^2=4#

The standard form of the equation for a circle with a center at #(h,k)# and radius #r# is

#(x-h)^2+(y-k)^2=r^2#

From the information provided, we know that #h=-7,k=-6,# and #r=2#, hence the equation

#(x-(-7))^2+(y-(-6))^2=2^2#

Which yields, when simplified

#(x+7)^2+(y+6)^2=4#

Graphed:

graph{((x+7)^2+(y+6)^2-4)((x+7)^2+(y+6)^2-.02)=0 [-17, 5, -10, 1]}