How do you find the equation of the circle with centre at (4,-1) and passing through (0,2)?

1 Answer
Feb 13, 2016

Answer:

#(x - 4)^2+(y+1)^2= 5^2 #

Explanation:

Here is the recipe for solving this type of problem:
1) Determine Radius: Find the distance between the point on the circle and center, that is the radius
2) Write the general circle equation form: #(x - h)^2+(y-k)^2= r^2 # where (h, k) is the center of the cicle

Step1 Radius - Use distance formula:
#r^2 =(x_1-x_1)^2 + (y_2-y_1)^2#
#r^2 =(4-0)^2 + (-1-2)^2 = 25#

Step2 Radius - Use distance formula:
#(x - 4)^2+(y+1)^2= 5^2 #