How do you find the equation of the circle with radius 6 and center (2,4)?
You can use the general relationship for the equation of a circle of center at
In your case:
The standard form of the equation of a circle is.
#color(red)(|bar(ul(color(white)(a/a)color(black)( (x - a )^2 + (y - b)^2 = r^2)color(white)(a/a)|)))#
where (a , b) are the coordinates of the centre and r , the radius
in this question a = 2 , b = 4 and r = 6
substitute these values into the standard equation
#rArr (x - 2)^2 + (y - 4)^2 = 36" is the equation " #