How do you find the equation of the secant line through the points where X has the given values: f(x) = x^2 + 2x; x=3, x=5?

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Answer 1 · 2015-10-16T15:53:07

A secant line is simply a linear equation and with two given points you can find the equation.

The two points on the secant line are:

$x = 3 and y = 3^2+2(3)= 15$ ; coordinate ( 3, 15 )

$x = 5 and y = 5^2+2(5)=$ ; coordinate ( 5, 35 )

slope of secant line = $=(35-15)/(5-3)=10$

Next, solve for the y-intercept:

$y=mx + b$

$15 = (10)(3)+b$

$b=-15$

secant line equation : $y=10x-15$

hope that helped