How do you find the equation of the secant line through the points where X has the given values: $h(x)=sqrt(x-5)$ ; x=6, x=9?

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Answer 1 · 2015-10-26T18:53:42

A secant line is a line through two points on the curve.

Find the two points, then find the equation of the line through them.

$y = h(x) = sqrt(x-5)$

When $x=6$ , we get $y = f(6) = sqrt((6)-5) = sqrt1 = 1$

One of the points is $(6,1)$

When $x=9$ , we get $y = f(9) = sqrt((9)-5) = sqrt4 = 2$

One of the points is $(9,2)$

Find the equation through the points $(6,1)$ and $(9,2)$ .

I assume that the student can finish this.

You should get $y=1/3x-1$

How do you find the equation of the secant line through the points where X has the given values: h(x)=sqrt(x-5)h(x)=sqrt(x-5); x=6, x=9?