# How do you find the equation of the tangent and normal line to the curve #y^3-3x-2y+6=0# at (9,3)?

##### 1 Answer

Equation of the tangent:

Equation of the normal:

#### Explanation:

Start by finding the derivative.

The slope of the tangent is given by substituting

Hence, the equation of the tangent, by point-slope form, is:

The equation of the normal line is simple: it is perpendicular to the tangent. A line perpendicular to another has a slope that is the negative reciprocal of the original line.

Thus, the slope of the normal is

Hopefully this helps!