# How do you find the equation of the tangent and normal line to the curve #y=(x+1)/(x-3) at x=2?

##### 1 Answer

Aug 6, 2016

Slope of tangent is

#### Explanation:

At

For finding equation, we need to find value of derivative of

=

and slope of tangent at

Now using point slope form

Slope of tangent is

Slope of normal is

graph{(y-(x+1)/(x-3))(4x+y-5)(x-4y-14)=0 [-16.5, 23.5, -13.68, 6.32]}