# How do you find the equation that represents the image of circle #(x- 5)^2 + (y + 12)^2 = 169# after a translation 2 units right and 3 units down?

##### 1 Answer

Jan 30, 2016

#### Answer:

Adjust to standard form to see what the original centre is, translate the centre, then plug back into the equation to find:

#(x-7)^2+(y-(-15))^2 = 13^2#

or:

#(x-7)^2+(y+15)^2=169#

#### Explanation:

The standard equation of a circle with centre

#(x-h)^2+(y-k)^2 = r^2#

With minor changes our starting equation is:

#(x-5)^2+(y-(-12))^2=13^2#

That is: It is a circle with centre

If translated

#(x-7)^2+(y-(-15))^2 = 13^2#

or putting it back in similar form to the starting equation:

#(x-7)^2+(y+15)^2=169#