# How do you find the equations for the normal line to #x^2-y^2=16# through (5,3)?

##### 1 Answer

Feb 27, 2017

Equation of normal is

#### Explanation:

Equation of normal at

As slope of tangent at

As

Hence slope of tangent at

Hence equation of normal is

graph{(3x+5y-30)(x^2-y^2-16)=0 [-7.125, 12.875, -2.68, 7.32]}