Question

How do you find the exact 6 trigonometric ratios for the angle x whose radian measure is `(5pi)/6`?

Answer 1

`sin [(5pi)/6] = sin (pi- pi/6) = sin (pi/6) = 1/2`

`cos [(5pi)/6)] = cos (Pi - Pi/6) = -cos (pi/6) = (-sqr3)/2`

`tan ((5pi)/6) = -1/(sqr3) = -(sqr3)/3`

`cot [(5pi)/6] = -sqr3`

`sec [(5pi)/6] = 2`

`csc [(5pi)/6] = -2/(sqr3)`