How do you find the exact functional value sin (-255 degrees) using the cosine sum or difference identity?

1 Answer
Sep 8, 2015

#sin(-255^@) = (1+sqrt(3))/(2sqrt(2))#

Explanation:

#sin(-255^@) = sin(105^@)#

#color(white)("XXXXXXX")=cos(90^@-105^@) = cos(-15^@)#

#color(white)("XXXXXXX")=cos(30^@-45^@)#

and by the cosine difference identity:
#color(white)("XXXXXXX")=cos(30^@) * cos(45^@)+sin(30^@) * sin(45^@)#

#color(white)("XXXXXXX")=sqrt(3)/2*1/sqrt(2)+1/2*1/sqrt(2)#

#color(white)("XXXXXXX")=(1+sqrt(3))/(2sqrt(2))#

and with the aid of a calculator:
#color(white)("XXXXXXX")~~0.965926# (but this is not "exact" as requested in question)