How do you find the exact value of #1/[cot(pi/4)] - 2/[csc(pi/6)]#? Trigonometry Right Triangles Trigonometric Functions of Any Angle 1 Answer Nghi N. Jun 8, 2015 #1/cot (pi/4) = tan(pi/4)# = 1 #csc (pi/6) = 1/sin (pi/6) = 1/(1/2) = 2# #2/csc(pi/6) = 2/2 = 1# #1/cot (pi/4) - 2/csc (pi/4) = 1 - 1 = 0# Answer link Related questions How do you find the trigonometric functions of any angle? What is the reference angle? How do you use the ordered pairs on a unit circle to evaluate a trigonometric function of any angle? What is the reference angle for #140^\circ#? How do you find the value of #cot 300^@#? What is the value of #sin -45^@#? How do you find the trigonometric functions of values that are greater than #360^@#? How do you use the reference angles to find #sin210cos330-tan 135#? How do you know if #sin 30 = sin 150#? How do you show that #(costheta)(sectheta) = 1# if #theta=pi/4#? See all questions in Trigonometric Functions of Any Angle Impact of this question 3224 views around the world You can reuse this answer Creative Commons License