How do you find the exact value of #12(sin150)(cos150)#?

1 Answer
Nov 27, 2016

#sin 150 = sin((5pi)/6) = 1/2#
#cos 150 = cos((5pi)/6) = -(sqrt(3))/2#

#12*1/2*(-(sqrt(3))/2)=-3sqrt(3)#

Explanation:

You have to know the three basic "magic" numbers of sin and cos goniometric functions. They are: #1/2#, #sqrt(2)/2#, #sqrt(3)/2#.

Also calculating with radians may help you.
You know that #1pi# rad equals 180°.

Here is the unit circle, where you can find all sin and cos values for the basic angles.

https://www.mathsisfun.com/geometry/unit-circle.html
I used an image from this page:
https://www.mathsisfun.com [online]. [cit. 2016-11-27]. Available from: https://www.mathsisfun.com/geometry/unit-circle.html