How do you find the exact value of #5(costheta-1)=6+costheta# in the interval #0<=theta<2pi#?
1 Answer
Jan 23, 2017
equation insolvable
Explanation:
5(cos t - 1) = 6 + cos t
5cos t - 5 = 6 + cos t
4cos t = 11
Problem insolvable because cos t must be
