How do you find the exact value of cos ((2pi)/9) cos (pi/18)+sin ((2pi)/9) sin (pi/18)cos(2π9)cos(π18)+sin(2π9)sin(π18)?

2 Answers

sqrt3/232

Explanation:

This is of the form cos(a-b)=cos (a)cos (b)+sin (a)sin (b)cos(ab)=cos(a)cos(b)+sin(a)sin(b)

The above expression simplifies to

cos (2pi/9 - pi/18)cos(2π9π18)
cos (3pi/18)cos(3π18)

cos (pi /6) = cos 30 = sqrt3/2cos(π6)=cos30=32

Dec 25, 2017

color (red)(sqrt3/2)32

Explanation:

we know that
color (cyan)(cos (A-B)=cosA×cosB+sinA×sinB)cos(AB)=cosA×cosB+sinA×sinB
similarly the equation given is question can be written as
cos (2pi/9-pi/18)cos(2π9π18)
cos ((4pi-pi)/18)cos(4ππ18)
cos (3pi/18)cos(3π18)
cos (pi/6)cos(π6)
cos ((180°)/6)
color (green)(cos (30°) = sqrt3/2)