How do you find the exact value of cos 5pi/4? Trigonometry Right Triangles Trigonometric Functions of Any Angle 1 Answer Alan P. Jun 1, 2016 #cos((5pi)/4)= -1/sqrt(2) or -sqrt(2)/2# Explanation: #(5pi)/4# is an angle in Quadrant III and as such (based on CAST) its #cos# is negative. #(5pi)/4=pi+pi/4# So its reference angle is #pi/4# which is a standard angle with #cos(pi/4)=1/sqrt(2)# Answer link Related questions How do you find the trigonometric functions of any angle? What is the reference angle? How do you use the ordered pairs on a unit circle to evaluate a trigonometric function of any angle? What is the reference angle for #140^\circ#? How do you find the value of #cot 300^@#? What is the value of #sin -45^@#? How do you find the trigonometric functions of values that are greater than #360^@#? How do you use the reference angles to find #sin210cos330-tan 135#? How do you know if #sin 30 = sin 150#? How do you show that #(costheta)(sectheta) = 1# if #theta=pi/4#? See all questions in Trigonometric Functions of Any Angle Impact of this question 90917 views around the world You can reuse this answer Creative Commons License