# How do you find the exact value of ln e^2+lne^5?

Jan 11, 2017

$\ln {e}^{2} + \ln {e}^{5} = 7$

#### Explanation:

Remember: $\ln {e}^{a} = a$

$\therefore \ln {e}^{2} + \ln {e}^{5} = 2 + 5 = 7$

Alternatively you could approach this problem as follows:

$\ln {e}^{2} + \ln {e}^{5} = \ln \left({e}^{2} \times {e}^{5}\right)$

$= \ln {e}^{7} = 7$