# How do you find the exact value of log_4 16^1.2?

Jan 18, 2017

I got $2.4$

#### Explanation:

I would first use a property of logs to deal with the exponent of the argument and write:
$1.2 {\log}_{4} \left(16\right) =$

Then I would use the definition to solve the log as:
${\log}_{4} \left(16\right) = 2$
[Because ${4}^{2} = 16$]

So I have:
$1.2 \cdot 2 = 2.4$