Question

How do you find the exact value of `sec(v-u)` given that `sinu=5/13` and `cosv=-3/5`?

Answer 1

Just simplify sec and enter values of cos and sin.

Explanation:

`sec(v-u)=1/cos(v-u)=1/(cosvcosu+sinvsinu)`
`sinu=5/13 Rightarrow cosu=sqrt(1-sin^2u) = +-12/13`
`cosv=-3/5 Rightarrow sinv =+-4/5`