How do you find the exact value of #sin (5pi)/3#? Trigonometry Right Triangles Trigonometric Functions of Any Angle 1 Answer Gaurang B. · Sep 25, 2015 0 for #sin(5pi)/3# and #-(sqrt3)/2# for #sin((5π)/3)# Explanation: #sin(5pi)/3=0/3=0# as #sin(kpi)=0# for all integer values of k For #sin((5π)/3)#, #sin((5π)/3)=sin((6π-π)/3)# #=sin(2π-π/3)# #=-sin(π/3)# #=-sqrt3/2# Answer link Related questions How do you find the trigonometric functions of any angle? What is the reference angle? How do you use the ordered pairs on a unit circle to evaluate a trigonometric function of any angle? What is the reference angle for #140^\circ#? How do you find the value of #cot 300^@#? What is the value of #sin -45^@#? How do you find the trigonometric functions of values that are greater than #360^@#? How do you use the reference angles to find #sin210cos330-tan 135#? How do you know if #sin 30 = sin 150#? How do you show that #(costheta)(sectheta) = 1# if #theta=pi/4#? See all questions in Trigonometric Functions of Any Angle Impact of this question 120065 views around the world You can reuse this answer Creative Commons License