How do you find the exact value of #sin(-90)#? Trigonometry Right Triangles Trigonometric Functions of Any Angle 1 Answer sankarankalyanam Mar 7, 2018 #sin (-90) = -1# Explanation: #sin -90 = sin (360 - 90) = sin 270# Angle #270^@# is third quadrant, where only tan and cot are positive. Hence #sin 270 = sin (180 + 90) = - sin 90 = -1# Answer link Related questions How do you find the trigonometric functions of any angle? What is the reference angle? How do you use the ordered pairs on a unit circle to evaluate a trigonometric function of any angle? What is the reference angle for #140^\circ#? How do you find the value of #cot 300^@#? What is the value of #sin -45^@#? How do you find the trigonometric functions of values that are greater than #360^@#? How do you use the reference angles to find #sin210cos330-tan 135#? How do you know if #sin 30 = sin 150#? How do you show that #(costheta)(sectheta) = 1# if #theta=pi/4#? See all questions in Trigonometric Functions of Any Angle Impact of this question 53916 views around the world You can reuse this answer Creative Commons License