How do you find the exact value of #tan pi/3#? Trigonometry Right Triangles Trigonometric Functions of Any Angle 1 Answer Truong-Son N. Apr 21, 2015 This is doable without using any complicated identities. #pi/3# radians #= 60^o# #tan 60^o = (sin 60^o) / (cos 60^o) = (sqrt(3)/2)/(1/2) = cancel(2)*sqrt(3)/cancel(2) = sqrt(3) ≈ 1.732# Answer link Related questions How do you find the trigonometric functions of any angle? What is the reference angle? How do you use the ordered pairs on a unit circle to evaluate a trigonometric function of any angle? What is the reference angle for #140^\circ#? How do you find the value of #cot 300^@#? What is the value of #sin -45^@#? How do you find the trigonometric functions of values that are greater than #360^@#? How do you use the reference angles to find #sin210cos330-tan 135#? How do you know if #sin 30 = sin 150#? How do you show that #(costheta)(sectheta) = 1# if #theta=pi/4#? See all questions in Trigonometric Functions of Any Angle Impact of this question 18187 views around the world You can reuse this answer Creative Commons License