How do you find the exact value of #cos(-(5pi)/12)# using the half angle formula?

1 Answer
Aug 30, 2015

#color(red)(cos(-(5π)/12) =sqrt(2–sqrt3)/2)#

Explanation:

The cosine half-angle formula is

#cos(x/2) = ±sqrt((1 + cos x) / 2)#

The sign is positive if #x/2# is in the first or fourth quadrant and negative if #x/2# is in the second or third quadrant.

#-(5π)/12# is in the fourth quadrant, so the sign is positive.

Also, #cos(-x) = cosx#, and

#(5π)/12 = 1/2×(5π)/6#

#cos(-(5π)/12) =cos((5π)/12) = cos(((5π)/6)/2) = sqrt((1+cos ((5π)/6))/2)#

#cos(-(5π)/12) =sqrt((1+cos (π - π/6))/2) == sqrt((1 – cos(π/6))/2)#

#cos(-(5π)/12) = sqrt((1 – (sqrt3)/2)/2) = sqrt((2 - sqrt3)/4)#

#cos(-(5π)/12) = sqrt(2 - sqrt3)/2#