Question

How do you find the exact values of cot, csc and sec for 60 degrees?

Answer 1

Find cot, csc and sec for 60 deg

Explanation:

Consider the right triangle A (60), B (90) and C (30).
AB is the short leg.
BC is the long leg.
AC is the hypotenuse.
`cos A = cos 60 = (AB)/(AC) = 1/2`
`sin A = sin 60 = (BC)/(AC) = sqrt3/2`
`cot 60 = cos/(sin) = (1/2)(2/sqrt3) = 1/sqrt3 = sqrt3/3`
`sec 60 = 1/(cos) = 2`
`csc 60 = 1/(sin) = 2/sqrt3 = (2sqrt3)/3`