# How do you find the explicit formula and calculate term 20 for -1, 6, 25, 62, 123?

##### 1 Answer

#### Answer:

Look at sequences of differences to construct a formula and find the

#### Explanation:

Each of the last 3 terms looks close to a cube, so I could guess the formula as

Write out the initial sequence:

#color(blue)(-1), 6, 25, 62, 123#

Write out the sequence of differences of that sequence:

#color(blue)(7), 19, 37, 61#

Write out the sequence of differences of that sequence:

#color(blue)(12), 18, 24#

Write out the sequence of differences of that sequence:

#color(blue)(6), 6#

Having reached a constant sequence, we can now use the first number of each sequence to write out a formula for

#a_n = color(blue)(-1)/(0!) +color(blue)(7)/(1!) (n-1) + color(blue)(12)/(2!) (n-1)(n-2) + color(blue)(6)/(3!) (n-1)(n-2)(n-3)#

#=-1+7(n-1)+6(n-1)(n-2)+(n-1)(n-2)(n-3)#

#=-1+7n-7+6n^2-18n+12+n^3-6n^2+11n-6#

#=n^3-2#

So