How do you find the first five terms given $a_{1} = 6$ $a_1=6$ and $a_{n + 1} = a_{n} + n + 3$ $a_(n+1)=a_n+n+3$ ?

Question

1417 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-10-11T16:41:43

First five term are ${6,10,15,21,28,......}$

As $a_(n+1)=a_n+n+3$

$a_2=a_1+1+3=6+1+3=10$

$a_3=a_2+2+3=10+2+3=15$

$a_4=a_3+3+3=15+3+3=21$

$a_5=a_4+4+3=21+4+3=28$

Hence first five term are ${6,10,15,21,28,...........}$

How do you find the first five terms given a_1=6a1=6a_1=6 and a_(n+1)=a_n+n+3an+1=an+n+3a_(n+1)=a_n+n+3?