How do you find the first five terms of each sequence a_1=1, a_2=2 a_(n+2)=4(a_(n+1))-3a_n?

${a}_{1} = 1$
${a}_{2} = 2$
$n = 1 : {a}_{3} = 4 {a}_{2} - 3 {a}_{1} = 8 - 3 = 5$
$n = 2 : {a}_{4} = 4 {a}_{3} - 3 {a}_{2} = 20 - 6 = 14$
$n = 3 : {a}_{5} = 4 {a}_{4} - 3 {a}_{3} = 56 - 15 = 41$