# How do you find the foci and sketch the ellipse #9x^2+4y^2=16#?

##### 1 Answer

May 12, 2017

The foci are

#### Explanation:

The general equation of the ellipse is

We compare this equation to

The center of the ellipse is

The major axis is vertical.

The other points are

We calculate

The foci are

With the points

graph{(9x^2+4y^2-16)((x)^2+(y-(sqrt20)/3)^2-0.001)((x)^2+(y-sqrt20/3)^2-0.001)=0 [-4.382, 4.386, -2.19, 2.197]}