# How do you find the foci and sketch the hyperbola x^2-y^2=1?

Feb 10, 2018

$\left(\pm 1 , 0\right)$ would be the foci

#### Explanation:

graph{x^2-y^2=1 [-10, 10, -5, 5]}

given equation of hyperbola, x^2−y^2=1

the general equation for hyperbolas with center at origin and foci on x axis is x^2/a^2−y^2/b^2=1, where the foci are $\left(\pm a ' 0\right)$

therefore, the foci for, x^2−y^2=1 is, $\left(\pm 1 , 0\right)$