How do you find the formula for $a_{n}$ $a_n$ for the arithmetic sequence $a_{1} = x, d = 2 x$ $a_1=x, d=2x$ ?

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Answer 1 · 2017-02-22T07:14:32

$a_{n} = (2 n - 1) x$ $a_n=(2n-1)x$

$n^{t h}$ $n^(th)$ term $a_{n}$ $a_n$ of an arithmetic sequence, whose first term is $a_{1}$ $a_1$ and common difference is $d$ $d$ is given by

$a_{n} = a_{1} + (n - 1) d$ $a_n=a_1+(n-1)d$

Here $a_{1} = x$ $a_1=x$ and $d = 2 x$ $d=2x$ , therefore $a_{n}$ $a_n$ is given by

$a_{n} = x + (n - 1) 2 x = x + (2 n - 2) x = (1 + 2 n - 2) x = (2 n - 1) x$ $a_n=x+(n-1)2x=x+(2n-2)x=(1+2n-2)x=(2n-1)x$

How do you find the formula for a_nana_n for the arithmetic sequence a_1=x, d=2xa1=x,d=2xa_1=x, d=2x?