How do you find the fourth term of $(2x+3y)^9$ ?

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Answer 1 · 2016-10-24T21:36:24

$217728x^6y^3$

Using binomial expansion, we know that the fourth term of $(2x+3y)^9 = (""^9"C"_4)(2x)^6(3y)^3=(216)(64x^6)(27y^3)=217728x^6y^3$

How do you find the fourth term of (2x+3y)^9(2x+3y)^9?