# How do you find the general form of the equation of this circle given Center(2,-3) ; containing point (5,-3)?

Feb 28, 2016

#### Answer:

${x}^{2} + {y}^{2} - 4 x + 6 y + 4 = 0$

#### Explanation:

As the distance between points $\left(2 , - 3\right)$ and $\left(5 , - 3\right)$ i.e. radius is $3$ and center of circle is $\left(2 , - 3\right)$, the equation of circle would be ${\left(x - 2\right)}^{2} + {\left(y + 3\right)}^{2} = {3}^{2}$ or ${x}^{2} - 4 x + 4 + {y}^{2} + 6 y + 9 = 9$ or
${x}^{2} + {y}^{2} - 4 x + 6 y + 4 = 0$.