Question

How do you find the general form of the equation of this circle given Center(2,-3) ; containing point (5,-3)?

Answer 1

`x^2+y^2-4x+6y+4=0`

Explanation:

As the distance between points `(2,-3)` and `(5,-3)` i.e. radius is `3` and center of circle is `(2,-3)`, the equation of circle would be `(x-2)^2+(y+3)^2=3^2` or `x^2-4x+4+y^2+6y+9=9` or
`x^2+y^2-4x+6y+4=0`.