How do you find the global extreme values for # y=x^2-6x-1# on [-2,2]?
The possible extreme points of such a function are:
1) vertex of the parabola
2) end points of the interval (in this case
First we calculate the vertex:
3 does not belong to the interval mentioned in the task, so we don't have to calculate
So we calculate:
Now we can write the answer.