Question

How do you find the gradient of the tangent to the curve `y=x^3` at the given value of x=4?

Answer 1

You start by evaluating the derivative `y'` of the function and then substitute `x=4` in it:

`y'(x)=3x^2`

substitute `x=4`;

`y'(4)=3*4^2=48` which is your gradient.