How do you find the horizontal asymptote for #F(x)=(x^2+x-12) / (x^2-4)#?

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Answer 1

Feb 28, 2016

see explanantion

Tony B

As #x# becomes very large the remaining elements have less and less influence.

We end up with#" " x^2/x^2 = 1#

#lim_(x->oo) (x^2+x-12)/(x^2-4) = x^2/x^2=+1#

#lim_(x->-oo) (x^2+x-12)/(x^2-4) = x^2/x^2=+1#