# How do you find the horizontal asymptote for (x-3)/(x-2)?

##### 1 Answer
Jul 9, 2016

Let $f \left(x\right) = \frac{x - 3}{x - 2}$.

Since the degree of the numerator and the denominator are both the same, namely $1$, then the horizontal asymptote is found by dividing the coefficient on the $x$-term on the numerator by the coefficient on the $x$-term on the denominator.

Horizontal asymptote: $\frac{x - 3}{x - 2} \to \frac{x}{x} \to \frac{1}{1} = 1 \to y = 1$.
Vertical asymptote: $\frac{x - 3}{x - 2} \to x - 2 = 0 \to x = 2$.